Question

encontre o valos de f(x)= x²+3 -10 para que f(x) =0

Answer 1

${x}^{2} + 3x - 10 = 0$

$d = {b}^{2} - 4ac$

$d = 9 - 4(1)( - 10)$

$d = 9 + 40$

$d = 49$

$x = \frac{ - b \frac{ + }{ - } \sqrt{d} }{2a}$

$x = \frac{ - 3 \frac{ + }{ - } 7}{2}$

$x1 = \frac{ - 3 + 7}{2} = \frac{4}{2} = 2$

$x2 = \frac{ - 3 - 7}{2} = \frac{ - 10}{2} = - 5$