Question

encontre o valor de x no triangulo retângulo

ME AJUDEM

Answer 1

13²=5²+x²
169=25+x²
x²+25=169
x²=169-25
x²=144
x=144(raiz)
x=12
AC=12

x²=9²+12²
x²=81+144
x²=225
x=225(raiz)
x=15
AD=15