Question

Encontre o termo geral da PG:
a) (-1,5,...)
b) (-2,-1,...)

Answer 1

$R= 5-(-1) \\ \\R= 5+1 \\ \\ R= 6 \\ \\ \\ an = a1+(n-1)*r \\ an=-1+n-1*6 \\ \boxed{\boxed{an=-1+n-6}}$


$R= -1-(-2) \\ \\ R= -1+2 \\ \\ R= 1 \\ \\ \\ an= -2+(n-1)*1 \\ an= -2+n-1*1 \\ \boxed{\boxed{an= -2+n-1}}$