Question

Encontre (g°f)(-2):sendo f(x)=2x-3 e g(x)=x+1

Answer 1

$gof = g(f(x))$

$g(f(x)) = g(2x - 3)$
$g(f(x)) = (2x - 3) + 1$
$g(f(x)) = 2x - 3 + 1$
$gof = 2x - 2$
$gof(-2)=2(-2)-2$
$gof(-2)=-4-2$
$gof(-2)=-6$

Answer 2

(g°f)(x) = g(f(x)) 

g(f(-2)) = g(2.(-2)-3) = g(-7)

g(-7) = -7 + 1
g(-7) = -6