Question

encontre as raízes X elevado a 2 + 6x - 16 = 0​

Answer 1

Resposta:

x²+6x-16=0

Δ=6²-4.1.(-16)

Δ=36+64

Δ=100

x1=-6+10/2=4/2=2

x2=-6-10/2=-16/2=-8

Explicação passo-a-passo:

Answer 2

Olá ^^

x² + 6x - 16 = 0

A= 1

B= 6

C= 16

∆= b² - 4ac

∆= 6² - 4 • 1 • 16

∆= 36 + 64

∆= 100

x= - b ± √∆ / 2a

x= - 6 ± √100 / 2 • 1

x'= - 6 + 10/2 = 4/2 = 2

x''= - 6 - 10/2 = - 16/2 = - 8

S= ( - 8, 2)