Question

encontre as raizes usando a formula de bhaskara x²+x-6=0

Answer 1

$Ol\acute{a},\;bom\;dia!\\\\x^2+x-6=0\\\\Coeficientes:\;a=1,\;b=1\;e\;c=-6\\\\\Delta=b^2-4ac\\\Delta=1^2-4\cdot1\cdot(-6)\\\Delta=1+24\\\Delta=25\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-1\pm\sqrt{25}}{2\cdot1}\\\\x=\dfrac{-1\pm5}{2}\\\\x_1=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{-1-5}{2}=\dfrac{-6}{2}=-3\\\\\\Espero\;ter\;ajudado.\\Bons\;estudos!\;=)$