Question

encontre as coordenadas do vértice dos seguintes
A) f(x) =${x}^{2} - 4x + 16$
B)f(x)=${x}^{2} + 5x + 4$

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Answer 1

a)

$Xv=\frac{-b}{2a} \\ Xv=\frac{-(-4)}{2.1}$

$Xv=\frac{4}{2} \\ Xv=2$

$\Delta=16-64=-48$

$Yv=\frac{-\Delta}{4a}\\Yv=\frac{-(-48)}{4.1}$

$Yv=\frac{48}{4} \\ Yv=12$

$V(Xv, Yv) \\ V(2,12)$