Question

Encontrar o termo geral da P.A.( 7/3, 11/4,...).​

Answer 1

$\large O ~termo ~geral ~da ~PA ~ \Rightarrow ~an = \dfrac{23}{12}+ \dfrac{5}{12}n$

                         $\Large Progress\tilde{a}o ~Aritm\acute{e}tica$

Encontrar a razão da PA;

$r = a2 - a1\\\\\\r = \dfrac{11}{4} - \dfrac{7}{3} \\\\\\r = \dfrac{5}{12}$

Com a razão da PA e o valor do termo  a1 encontrar o termo geral.

$an = a1 + ( n -1) . r\\\\\\an = \dfrac{7}{3} + ( n -1) . \dfrac{5}{12}\\\\\\an = \dfrac{7}{3} +\dfrac{5}{12}n - \dfrac{5}{12}\\\\\\an = \dfrac{23}{12}+ \dfrac{5}{12}n$  

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