Em um Prisma hexagonal regular de aresta lateral 6 cm e aresta da base 3 cm calcule a area da base, area lateral e area total
Soluções para a tarefa
Respondido por
134
h = 6 cm
a = 3 cm
Ab = 3a²√3 / 2
Ab = 3(3²)√3 / 2
Ab = 27√3 / 2 cm²
_________________________________________
Al = 6Af
Al = 6(6*3)
Al = 6*18
Al = 108 cm²
___________________________________________
At = 2Ab + Al
At = 2(27√3/2) + 108
At = 27√3 + 108
At = 27(√3+4) cm²
a = 3 cm
Ab = 3a²√3 / 2
Ab = 3(3²)√3 / 2
Ab = 27√3 / 2 cm²
_________________________________________
Al = 6Af
Al = 6(6*3)
Al = 6*18
Al = 108 cm²
___________________________________________
At = 2Ab + Al
At = 2(27√3/2) + 108
At = 27√3 + 108
At = 27(√3+4) cm²
Respondido por
14
Explicação passo-a-passo:
h = 6 cm
a = 3 cm
Ab = 3a²√3 / 2
Ab = 3(3²)√3 / 2
Ab = 27√3 / 2 cm²
_________________________________________
Al = 6Af
Al = 6(6*3)
Al = 6*18
Al = 108 cm²
___________________________________________
At = 2Ab + Al
At = 2(27√3/2) + 108
At = 27√3 + 108
At = 27(√3+4) cm²
Perguntas interessantes