Matemática, perguntado por moonkjkk, 4 meses atrás

Em cada uma das fichas a seguir , a letra representa um número e as frações são equivalentes . Determine o número correspondente a cada letra .

A 16
— = –
5 20


6 3
— = –
B 7


81 9 D
— = – = —
C 13 39


———————————————————

Das frações a seguir , copie apenas as irredutíveis .

14

5


7

12


16

4


21

5

4

17


24

36

6

20


Agora , simplifique as frações da questão anterior que você não copiou , até torna - Las irredutíveis .



Soluções para a tarefa

Respondido por mariambsilva111
1

Resposta:

Resolução:

\begin{gathered}\mathsf{\dfrac{A}{5}=\dfrac{16}{20}}\\\\\\\mathsf{A=\dfrac{16\cdot 5}{20}}\\\\\\\mathsf{A=\dfrac{\diagup \!\!\!\!\! 4\cdot 4\cdot \diagup \!\!\!\!5}{\diagup \!\!\!\!5\cdot \diagup \!\!\!\!\!4}}\\\\\\\boxed{\mathsf{A=4}}\: \: \checkmark\end{gathered}

5

A

=

20

16

A=

20

16⋅5

A=

╱5⋅╱4

╱4⋅4⋅╱5

A=4

- - - - -

\begin{gathered}\mathsf{\dfrac{6}{B}=\dfrac{3}{7}}\\\\\\\mathsf{3B=6\cdot 7}\\\\\\\mathsf{B=\dfrac{6\cdot 7}{3}}\\\\\\\mathsf{B=\dfrac{2\cdot \diagup \!\!\!\!\! 3\cdot 7}{\diagup \!\!\!\!\!3}}\\\\\\\mathsf{B=2\cdot 7}\\\\\\\boxed{\mathsf{B=14}}\: \: \checkmark\end{gathered}

B

6

=

7

3

3B=6⋅7

B=

3

6⋅7

B=

╱3

2⋅╱3⋅7

B=2⋅7

B=14

- - - - -

\begin{gathered}\mathsf{\dfrac{81}{C}=\dfrac{9}{13}}\\\\\\\mathsf{9C=81\cdot 13}\\\\\\\mathsf{C=\dfrac{81\cdot 13}{9}}\\\\\\\mathsf{C=\dfrac{\diagup \!\!\!\! 9\cdot 9\cdot 13}{\diagup \!\!\!\!9}}\\\\\\\mathsf{C=9\cdot 13}\\\\\\\boxed{\mathsf{C=117}}\: \: \checkmark\end{gathered}

C

81

=

13

9

9C=81⋅13

C=

9

81⋅13

C=

╱9

╱9⋅9⋅13

C=9⋅13

C=117

- - - - -

\begin{gathered}\mathsf{\dfrac{9}{13}=\dfrac{D}{39}}\\\\\\\mathsf{D=\dfrac{9\cdot 39}{13}}\\\\\\\mathsf{D=\dfrac{9\cdot 3\cdot \diagup \!\!\!\!\!\! 13}{\diagup \!\!\!\!\!\!13}}\\\\\\\mathsf{D=9\cdot 3}\\\\\\\boxed{\mathsf{D=27}}\: \: \checkmark\end{gathered}

13

9

=

39

D

D=

13

9⋅39

D=

╱13

9⋅3⋅╱13

D=9⋅3

D=27

- - - - -

\begin{gathered}\mathsf{\dfrac{6}{11}=\dfrac{48}{E}}\\\\\\\mathsf{6E=48\cdot 11}\\\\\\\mathsf{E=\dfrac{48\cdot 11}{6}}\\\\\\\mathsf{E=\dfrac{8\cdot \diagup \!\!\!\! 6\cdot 11}{\diagup \!\!\!\!6}}\\\\\\\mathsf{E=8\cdot 11}\\\\\\\boxed{\mathsf{E=88}}\: \: \checkmark\end{gathered}

11

6

=

E

48

6E=48⋅11

E=

6

48⋅11

E=

╱6

8⋅╱6⋅11

E=8⋅11

E=88

- - - - -

\begin{gathered}\mathsf{\dfrac{6}{11}=\dfrac{F}{33}}\\\\\\\mathsf{11F=33\cdot 6}\\\\\\\mathsf{F=\dfrac{33\cdot 6}{11}}\\\\\\\mathsf{F=\dfrac{3\cdot \diagup \!\!\!\!\! 11\cdot 6}{\diagup \!\!\!\!\! 11}}\\\\\\\mathsf{F=3\cdot 6}\\\\\\\boxed{\mathsf{F=18}}\: \: \checkmark\end{gathered}

11

6

=

33

F

11F=33⋅6

F=

11

33⋅6

F=

╱11

3⋅╱11⋅6

F=3⋅6

F=18


mariambsilva111: não sei se está certo mais espero que sim
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