Em cada uma das fichas a seguir , a letra representa um número e as frações são equivalentes . Determine o número correspondente a cada letra .
A 16
— = –
5 20
6 3
— = –
B 7
81 9 D
— = – = —
C 13 39
———————————————————
Das frações a seguir , copie apenas as irredutíveis .
14
—
5
7
—
12
16
—
4
21
—
5
4
—
17
24
—
36
6
—
20
Agora , simplifique as frações da questão anterior que você não copiou , até torna - Las irredutíveis .
Soluções para a tarefa
Resposta:
Resolução:
\begin{gathered}\mathsf{\dfrac{A}{5}=\dfrac{16}{20}}\\\\\\\mathsf{A=\dfrac{16\cdot 5}{20}}\\\\\\\mathsf{A=\dfrac{\diagup \!\!\!\!\! 4\cdot 4\cdot \diagup \!\!\!\!5}{\diagup \!\!\!\!5\cdot \diagup \!\!\!\!\!4}}\\\\\\\boxed{\mathsf{A=4}}\: \: \checkmark\end{gathered}
5
A
=
20
16
A=
20
16⋅5
A=
╱5⋅╱4
╱4⋅4⋅╱5
A=4
✓
- - - - -
\begin{gathered}\mathsf{\dfrac{6}{B}=\dfrac{3}{7}}\\\\\\\mathsf{3B=6\cdot 7}\\\\\\\mathsf{B=\dfrac{6\cdot 7}{3}}\\\\\\\mathsf{B=\dfrac{2\cdot \diagup \!\!\!\!\! 3\cdot 7}{\diagup \!\!\!\!\!3}}\\\\\\\mathsf{B=2\cdot 7}\\\\\\\boxed{\mathsf{B=14}}\: \: \checkmark\end{gathered}
B
6
=
7
3
3B=6⋅7
B=
3
6⋅7
B=
╱3
2⋅╱3⋅7
B=2⋅7
B=14
✓
- - - - -
\begin{gathered}\mathsf{\dfrac{81}{C}=\dfrac{9}{13}}\\\\\\\mathsf{9C=81\cdot 13}\\\\\\\mathsf{C=\dfrac{81\cdot 13}{9}}\\\\\\\mathsf{C=\dfrac{\diagup \!\!\!\! 9\cdot 9\cdot 13}{\diagup \!\!\!\!9}}\\\\\\\mathsf{C=9\cdot 13}\\\\\\\boxed{\mathsf{C=117}}\: \: \checkmark\end{gathered}
C
81
=
13
9
9C=81⋅13
C=
9
81⋅13
C=
╱9
╱9⋅9⋅13
C=9⋅13
C=117
✓
- - - - -
\begin{gathered}\mathsf{\dfrac{9}{13}=\dfrac{D}{39}}\\\\\\\mathsf{D=\dfrac{9\cdot 39}{13}}\\\\\\\mathsf{D=\dfrac{9\cdot 3\cdot \diagup \!\!\!\!\!\! 13}{\diagup \!\!\!\!\!\!13}}\\\\\\\mathsf{D=9\cdot 3}\\\\\\\boxed{\mathsf{D=27}}\: \: \checkmark\end{gathered}
13
9
=
39
D
D=
13
9⋅39
D=
╱13
9⋅3⋅╱13
D=9⋅3
D=27
✓
- - - - -
\begin{gathered}\mathsf{\dfrac{6}{11}=\dfrac{48}{E}}\\\\\\\mathsf{6E=48\cdot 11}\\\\\\\mathsf{E=\dfrac{48\cdot 11}{6}}\\\\\\\mathsf{E=\dfrac{8\cdot \diagup \!\!\!\! 6\cdot 11}{\diagup \!\!\!\!6}}\\\\\\\mathsf{E=8\cdot 11}\\\\\\\boxed{\mathsf{E=88}}\: \: \checkmark\end{gathered}
11
6
=
E
48
6E=48⋅11
E=
6
48⋅11
E=
╱6
8⋅╱6⋅11
E=8⋅11
E=88
✓
- - - - -
\begin{gathered}\mathsf{\dfrac{6}{11}=\dfrac{F}{33}}\\\\\\\mathsf{11F=33\cdot 6}\\\\\\\mathsf{F=\dfrac{33\cdot 6}{11}}\\\\\\\mathsf{F=\dfrac{3\cdot \diagup \!\!\!\!\! 11\cdot 6}{\diagup \!\!\!\!\! 11}}\\\\\\\mathsf{F=3\cdot 6}\\\\\\\boxed{\mathsf{F=18}}\: \: \checkmark\end{gathered}
11
6
=
33
F
11F=33⋅6
F=
11
33⋅6
F=
╱11
3⋅╱11⋅6
F=3⋅6
F=18
✓