Matemática, perguntado por Vitória123454, 11 meses atrás

Efetue, dando o resultado na forma irredutível: a) 3/4 + 5/6 - 1/2 = b) 2 + 1/2 - 3/4 = c) 3 - (5/6 + 1/2) = -d) 3/5 + 6/5 - 1/3 =

Soluções para a tarefa

Respondido por luanamillerszp6o8v7
9

Resposta:

A = 13/12

B = 7/4

C = 22/15

Explicação passo-a-passo:

A) \frac{3}{4} + \frac{5}{6} - \frac{1}{2} \\ \\\frac{(6*3) +(5*4)}{4 X 6} = \frac{18 + 20}{24} = \frac{38}{24} - \frac{1}{2}\\\ \\ \frac{38}{24} - \frac{1}{2} = \frac{(2*38) - (24*1)}{24*2} = \frac{76 - 24}{48} = \frac{52}{48} = \frac{52/4}{48/4} = \frac{13}{12}\\ \\ </p><p>[tex]B) 2 + \frac{1}{2} - \frac{3}{4} \\ \\\frac{2}{1} + \frac{1}{2} = \frac{(2*2) + (1*1)}{1*2} = \frac{4+ 1}{2} = \frac{5}{2}\\ \\\frac{5}{2} - \frac{3}{4} = \frac{(5*4) - (2*3)}{2*4} = \frac{20 - 6}{8} = \frac{14/2}{8/2} = \frac{7}{4} = \\\\\\

C = \frac{3}{1} - (\frac{5}{6} + \frac{1}{2}) = \\\\\frac{(5*2) + (6*1)}{6*2} =  \frac{10 + 6}{12} = \frac{16}{12} = \frac{16/4}{12/4} = \frac{4}{3}    \\\\\frac{3}{1} - \frac{4}{3} = \frac{(3*3) - (1*4)}{1*3} = \frac{9 - 4}{3} = \frac{5}{3}D = \frac{3}{5} + \frac{6}{5} - \frac{1}{3}   = \\\\= \frac{(3*5) + (6*5)}{5*5} = \frac{15 + 30}{25}  = \frac{45}{25} = \frac{45/5}{25/5} = \frac{9}{5}    \\\\\frac{9}{5} - \frac{1}{3}  = \frac{(3*9) - (5*1)}{5*3} = \frac{27 - 5}{15} = \frac{22}{15}


espero ter ajudado

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