Matemática, perguntado por hellenvieirali, 10 meses atrás

efetue
a)(1/2+1/4-3/8)÷11/2=
b)(2/3-1/6)÷(1/3+1/6)=
c )(1/4+1/3)÷(5/2+2/3)=
d)5/12+[2-(1/3.3/5)÷1/5]=
e)(2+1/4).5+(3-1/3).3/2=

Soluções para a tarefa

Respondido por pv123Vieira
5
Efetue :
a)(1/2+1/4-3/8)÷11/2=
(4+2-3)/8 ÷11/2
3/8÷11/2= inverta o sinal para multiplicação e a segunda fração=3/8X2/11=6/88=3/44
b)(2/3-1/6)÷(1/3+1/6)=
   (4-1/6)÷(2+1/6)
      3/6÷3/6 =
       3/6x6/3=
     1/2X2=
      2/2=1
c )(1/4+1/3)÷(5/2+2/3)=
 (3+4/12)÷(15+4/6)
   7/12÷19/6
7/12÷38/12
7/12X12/38
84/456=7/38


   

d)5/12+[2-(1/3.3/5)÷1/5]=
5/12+[2- 1/5÷1/5]
5/12+[2-1/5X5]
5/12+[2-1]
5/12+1
5+12/12=17/12
e)(2+1/4).5+(3-1/3).3/2=
(8+1/4).+5+(9-1/3).3/2
[9/4 .+5]+[8/3.3/2]
45/4+4
45+16/4=61/4

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