Dividir 284 em partes inversamente proporcionais a 3,5 e 7 ???????
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k.(1/3+1/5+1/7)=284
mmc:
3,5,7/3
1,5,7/5
1,1,7/7
1,1,1=>3.5.7=>105
k.(1/3+1/5+1/7)=284
k.(35+21+15)/105=284
k.(71/105)=284
71k=284.(105)
k=284.105/71
k=29.820/71
k=420
x=1/3.(420)=140
y=1/5.(420)=84
z=1/7.(420)=60
x=140
y=84
z=60
mmc:
3,5,7/3
1,5,7/5
1,1,7/7
1,1,1=>3.5.7=>105
k.(1/3+1/5+1/7)=284
k.(35+21+15)/105=284
k.(71/105)=284
71k=284.(105)
k=284.105/71
k=29.820/71
k=420
x=1/3.(420)=140
y=1/5.(420)=84
z=1/7.(420)=60
x=140
y=84
z=60
davidjunior17:
Olá, destruidor!!
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Resposta: As partes são 140, 84 e 60
Explicação passo-a-passo:
x/3+x/5+x/7=284
MMC 3 5 7 | 3
1 5 7 | 5
1 1 7 | 7
1 1 1 | 3*5*7=105
105/3+105/5+105/7=
35x+21x+15x/105=
71x=284*105
71x=29820
x=29820/71
x=420
x=420/3=140
x=420/5=84
x=420/7=60
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