Question

Divida o número 441 em partes inversamente proporcionais aos números 6, 10 e 12.

Answer 1

$> \: resolucao \\ \\ \geqslant \: grandezas \: inversamente \\ proporcional \\ \\ \frac{x}{6} + \frac{x}{10} + \frac{x}{12} = 441 > mmc = 60 \\ \\ \frac{10x + 6x + 5x}{60} = \frac{26460}{60} \\ \\ 21x = 26460$

$x = \frac{26460}{21} \\ \\ x = 1260$

$\frac{x}{6} = \frac{1260}{6} = 210 \\ \\ \frac{x}{10} = \frac{1260}{10} = 126 \\ \\ \frac{x}{12} = \frac{1260}{12} = 105 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$