Question

detrrmine o conjunto da solução da equação X2 + 2X – 3 = 0 *
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Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~x^{2}+2x-3=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=2~e~c=-3\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(2)^{2}-4(1)(-3)=4-(-12)=16\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(2)-\sqrt{16}}{2(1)}=\frac{-2-4}{2}=\frac{-6}{2}=-3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(2)+\sqrt{16}}{2(1)}=\frac{-2+4}{2}=\frac{2}{2}=1\\\\S=\{-3,~1\}$

Answer 2

x2+2x-3=0

0=x2+2x-3

0=4x-3

0=1x

x=0/1

resposta= 0/1

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