Question

Determine um número real "a" para que as expressões (3a + 6)/ 8 e (2a + 10)/6 sejam iguais

Answer 1

$\mathrm{\dfrac{3a+6}{8}=\dfrac{2a+10}{6}\ \to\ \dfrac{3(a+2)}{4}=\dfrac{2(a+5)}{3}}\\\\ \mathrm{3.3(a+2)=4.2(a+5)\ \to\ 9(a+2)=8(a+5)}\\\\ \mathrm{9a+18=8a+40\ \to\ 9a-8a=40-18}\\\\ \boxed{\mathbf{a=22}}$

Answer 2

Boa tarde Felipe

(3a + 6)/8 = (2a + 10)/6

6*(3a + 6) = 8*(2a + 10)

18a + 36 = 16a + 80

18a - 16a = 80 - 36

2a = 44 

a = 22