Question

Determine os zeros das seguintes funções:
Y= -3x²-8x+3
Y= 4x²+x-5
Y= 9x²-6x+1

Answer 1

y= -3x^2-8x+3

Delta: (-8)^2-4 (-3)(3) = 64 + 36 = 100

-(-8) +/- 10
--------------
2 (-3)

x'= 8 + 10
-------------
-6

18
--- = - 3
-6

x"= 8-10
-----------
-6

-2
--- = - 1/3
-6


y= 4x^2+x-5

Delta: (1)^2-4 (4)(-5) = 1+ 80 = 81

-(1) +/- 9
------------
2 (1)

X'= -1 + 9
--------------
2

-8
--- = -4
2

x"= -1 - 9
-------------
2

-10
----- = -5
2


y= 9x^2-6x+1

Delta: (-6)^2-4(9)(1) = 36-36 = 0

-(-6)+/- 0
-------------
2 (9)

x'= 6+0
-----------
18

6
--- = 1/3
18

x"= 6-0
-----------
18

6
--- = 1/3
18