Question

determine os zeros da função

Answer 1

Raizes são os "x" que zeram a função, logo:

-2x² + 7x - 3 = 0

a = -2 ; b = 7 ; c = -3

Utilizando Bhaskara:

Δ = b² - 4.a.c

Δ = 7² - 4.(-2).(-3)

Δ = 49 - 24

Δ = 25

$x=\frac{-b \pm \sqrt{\Delta}}{2a}\\\\x = \frac{-7 \pm \sqrt{25}}{2.(-2)}\\\\x = \frac{-7 \pm 5}{-4}\\\\\\x_1= \frac{-7 + 5}{-4}=\frac{-2}{-4}=\frac{1}{2}\\\\x_2= \frac{-7 - 5}{-4}=\frac{-12}{-4}=3$

Portanto as raizes são x1 = 1/2 e x2 = 3