Question

determine os valores de x e y

Answer 1

Explicação passo-a-passo:

b)

=> Valor de x

Seja AH a altura relativa à hipotenusa do triângulo ABC

Pelo Teorema de Pitágoras, no triângulo retângulo ABH:

$\sf x^2+4,8^2=8$

$\sf x^2+23,04=64$

$\sf x^2=64-23,04$

$\sf x^2=40,96$

$\sf x=\sqrt{40,96}$

$\sf \red{x=6,4}$

=> Valor de y

$\sf x+y=10$

$\sf 6,4+y=10$

$\sf y=10-6,4$

$\sf \red{y=3,6}$

c)

=> Valor de x

$\sf \dfrac{x}{27}=\dfrac{14}{18}$

$\sf 18x=27\cdot14$

$\sf 18x=378$

$\sf x=\dfrac{378}{18}$

$\sf \red{x=21}$

=> Valor de y

$\sf \dfrac{y}{27}=\dfrac{16}{18}$

$\sf 18y=27\cdot16$

$\sf 18y=432$

$\sf y=\dfrac{432}{18}$

$\sf \red{y=24}$

d)

=> Valor de x

$\sf \dfrac{x}{3}=\dfrac{8}{6}$

$\sf 6x=3\cdot8$

$\sf 6x=24$

$\sf x=\dfrac{24}{6}$

$\sf \red{x=4}$

=> Valor de y

$\sf \dfrac{y}{3}=\dfrac{4}{6}$

$\sf 6y=3\cdot4$

$\sf 6y=12$

$\sf y=\dfrac{12}{6}$

$\sf \red{y=2}$