Question

determine os valores de a,b,c nas identidades de polinomios 5x²-4+2c=(a-1)x²+2bx-10

Answer 1

Olá!

$\mathtt{5x^2 - 4x + 2c = (a-1)x^2 + 2bx - 10}$

• Iguale os termos semelhantes:

$\begin{cases} \mathtt{(a - 1) x^2 = 5 x^2} \\ \mathtt{2bx = -4 x} \\ \mathtt{2c = -10} \end{cases}$

$\begin{cases} \mathtt{(a - 1) \cancel{x^2} = 5 \cancel{x^2}} \\ \mathtt{2b\cancel{x} = -4 \cancel{x}} \\ \mathtt{2c = -10} \end{cases}$

$\begin{cases} \mathtt{a - 1 = 5} \\ \mathtt{2b= -4} \\ \mathtt{2c = -10} \end{cases}$

$\begin{cases} \mathtt{a = 6} \\ \mathtt{b= -2} \\ \mathtt{c = -5} \end{cases}$

$\textbf{Prova:}$

$\mathtt{5x^2 -4x + 2 (-5) = (6-1)x^2 +2(-2)x - 1} \\ \mathtt{5x^2 - 4x -10 = 5x^2 -4x - 10}$

Bons estudos :::)