Determine o Zeros :
A) f(x)= ax2-3x+2
B) f(x)=2x2+12x+18
C)f(x)=x2-2x+3
Soluções para a tarefa
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a) x² - 3x + 2 = 0
a = 1; b = -3; c = 2
x = [- b ± √(b² - 4ac)] / 2a
x = [- (-3) ± √([-3]² - 4 . 1 . 2)] / 2 . 1
x = [3 ± √(9 - 8)] / 2
x = [3 ± √1] / 2
x = [3 ± 1] / 2
x' = [3 - 1] / 2 = 2 / 2 = 1
x'' = [3 + 1] / 2 = 4 / 2 = 2
S = {1, 2}
b) 2x² + 12x + 18 = 0
x = [- 12 ± √(12² - 4 . 2 . 18)] / 2 . 2
x = [- 12 ± √(144 - 144)] / 4
x = [- 12 ± √0] / 4
x = [- 12 ± 0] / 4
x' = [- 12 - 0] / 4 = -12 / 4 = -3
x'' = [- 12 + 0] / 4 = -12 / 4 = -3
S = {-3}
c) x² - 2x + 3 = 0
x = [- (-2) ± √([-2]² - 4 . 1 . 3)] / 2 . 1
x = [2 ± √(4 - 12)] / 2
x = [2 ± √-8] / 2
x ∉ R
Espero ter ajudado. Valeu!
a = 1; b = -3; c = 2
x = [- b ± √(b² - 4ac)] / 2a
x = [- (-3) ± √([-3]² - 4 . 1 . 2)] / 2 . 1
x = [3 ± √(9 - 8)] / 2
x = [3 ± √1] / 2
x = [3 ± 1] / 2
x' = [3 - 1] / 2 = 2 / 2 = 1
x'' = [3 + 1] / 2 = 4 / 2 = 2
S = {1, 2}
b) 2x² + 12x + 18 = 0
x = [- 12 ± √(12² - 4 . 2 . 18)] / 2 . 2
x = [- 12 ± √(144 - 144)] / 4
x = [- 12 ± √0] / 4
x = [- 12 ± 0] / 4
x' = [- 12 - 0] / 4 = -12 / 4 = -3
x'' = [- 12 + 0] / 4 = -12 / 4 = -3
S = {-3}
c) x² - 2x + 3 = 0
x = [- (-2) ± √([-2]² - 4 . 1 . 3)] / 2 . 1
x = [2 ± √(4 - 12)] / 2
x = [2 ± √-8] / 2
x ∉ R
Espero ter ajudado. Valeu!
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