Question

determine o vertice v da parabola que representa a funcao quadratica:
a) y=x²
b)y=(x-2)²+3

Answer 1

a)

y = x²
Δ = b² - 4ac
Δ = 0 - 4.1.0
Δ = 0

xv = -b/2a
xv = 0/2.1

xv = 0

yv = -Δ/4a
yv = 0/4

yv = 0

$\Large\boxed{V(0,0)}$

b) y = (x-2)² + 3
y = x² - 4x + 4 + 3
y = x² -4x + 7

Δ = 16 - 28
Δ = -12

xv = -b/2a
xv = 4/2

xv = 2

yv = -Δ/4a
yv = 12/4

yv = 3

$\Large\boxed{V(2,3)}$