Question

determine o vertice das funçoes : f(x)=2x²×3x+1

Answer 1

$Vertice( -\frac{ \\ b}{2a} ,- \frac{b^{2} -4ac}{4a} ) \\ \\ f(x)=2x^2+3x+1 \\ \\ x_{vertice} = -\frac{ \\ b}{2a}=-\frac{3}{2(2)} =- \frac{3}{4} \\ \\ y_{vertice} = - \frac{b^{2} -4ac}{4a}=-\frac{3^{2} -4(2)(1)}{4(2)}= -\frac{1}{8} \\ \\ Resposta \\ \\ Vertice(- \frac{3}{4} ,-\frac{1}{8} )$