Question

determine o vertice da parabola da funçao y=x2-7x+12

Answer 1

$x^{2} -7x+12 \\ \\ a=1 \\ b=-7 \\ c=12 \\ \\ delta= b^{2}-4ac \\ delta= (-7)^{2}-4(1)(12) \\ delta=49-48 \\ delta=1 \\ \\ Vertice \\ V= -\frac{b}{2a} , \frac{delta}{4a} \\ \\ -\frac{b}{2a} = \frac{-(-7)}{2(1)}= \frac{7}{2} \\ \frac{delta}{4a}= \frac{1}{4(1)}= \frac{1}{4} \\ \\ Vertice = \frac{7}{2}, \frac{1}{4}$