Question

determine o vértice da parábola da função f(x) = x ao quadrado -5x+6

Answer 1

 f(x) = x^2 -5x+6

delta = (-5)^2 - 4.1.6 = 25 - 24 = 1

Vertice : V (xv, Yv)


Xv = - b   = -(-5) ==> Xv = 5
          2a       2.1                  2

Yv = - delta = - 1 ==>Yv = - 1
             4a       4.1                4

Answer 2

$x_V=-\dfrac{b}{2a}=-\dfrac{-5}{2\cdot1}=\dfrac{5}{2}\\\\ y_V=-\dfrac{\Delta}{4a}=-\dfrac{b^2-4\cdot a\cdot c}{4a}=-\dfrac{(-5)^2-4\cdot1\cdot6}{4\cdot1}=-\dfrac{25-24}{4}=-\dfrac{1}{4}\\\\\\ \boxed{V(\dfrac{5}{2},-\dfrac{1}{4})}$