Question

determine o valor numérico de f(0) + f (3/2) - f(1)

Answer 1

Resposta:

f(0)+f(3/2)-f(1)= -1/3

Explicação passo-a-passo:

f(0)=f(x) => x=0 => -1≤x≤1 => f(x)=2ˣ

f(0)=2⁰=1

f(3/2)=f(x) => x=3/2=1,5 => x>1 => f(x)=1/x

f(3/2)=1÷(3/2)=1×(2/3)=2/3

f(1)=f(x) => x=1 => -1≤x≤1 => f(x)=2ˣ

f(1)=2¹=2

f(0)+f(3/2)-f(1)=1+2/3-2=2/3-1=(2-3)/3= -1/3