Question

determine o valor de x em cada uma das seguintes proporções:

a) x/7=9/63

b)8/32=2/x

c)2/10=3/2x

d)3,7/11=x/55

e)2/9=x+8/x+50

responda se tiver certeza da resposta caso contrario denunciarei ╮(＾▽＾)╭​

Answer 1

$a)\\\\\frac{x}{7}=\frac{9}{63}\\\\\frac{x}{7}=\frac{1}{7}\\\\\frac{7x}{7}=\frac{1\cdot \:7}{7}\\\\x=1$     $b)\\\\\frac{8}{32}=\frac{2}{x}\\\\8x=32\cdot \:2\\\\8x=64\\\\\frac{8x}{8}=\frac{64}{8}\\\\x=8$     $c)\\\\\frac{2}{10}=\frac{3}{2x}\\\\2\cdot \:2x=10\cdot \:3\\\\4x=30\\\\\frac{4x}{4}=\frac{30}{4}\\\\x=\frac{15}{2}$    

$d)\\\\\frac{3.7}{11}=\frac{x}{55}\\\\\frac{x}{55}=\frac{3.7}{11}\\\\\frac{55x}{55}=\frac{3.7\cdot \:55}{11}\\\\\frac{55}{55}=1\\\\\frac{3.7\cdot \:55}{11}\\\\3.7\cdot \:55=203.5\\\\\frac{203.5}{11}=18.5\\\\x=18.5$                 $e)\\\\\frac{2}{9}=\frac{x+8}{x+50}\\\\2\left(x+50\right)=9\left(x+8\right)\\\\2x+100=9x+72\\\\2x+100-100=9x+72-100\\\\2x=9x-28\\\\2x-9x=9x-28-9x\\\\-7x=-28\\\\\frac{-7x}{-7}=\frac{-28}{-7}\\\\x=4$