Question

Determine o valor de x em cada item.


$\sqrt[]{x} =1\\\sqrt[]{x} =5\\\sqrt[]{x} =6,2\\\sqrt[]{x} =4,3\\\sqrt[]{x} =0,7\\\sqrt[]{x} =3,1$

Answer 1

$\sqrt{x} =1\implies {( \sqrt{x})}^{2} = {1}^{2} \implies x = 1 \\ \\\sqrt{x} =5\implies {( \sqrt{x})}^{2} = {5}^{2} \implies x = 25 \\ \\ \sqrt{x} =6,2\implies {( \sqrt{x})}^{2} = {6,2}^{2} \implies x = 38,44 \\ \\ \sqrt{x} =4,3\implies {( \sqrt{x})}^{2} = {4,3}^{2} \implies x = 18,49 \\ \\ \sqrt{x} =0,7\implies {( \sqrt{x})}^{2} = {0,7}^{2} \implies x = 0,49 \\ \\ \sqrt{x} =3,1\implies {( \sqrt{x})}^{2} = {3,1}^{2} \implies x = 9,61$

Answer 2

Para eliminar a raiz quadrada e insolar o X, basta elevar os dois lados da igualdade ao quadrado

$\sqrt{x} = 1 \\ { \sqrt{x} }^{2} = {1}^{2} \\ x = 1$

$\sqrt{x} = 5 \\ { \sqrt{x} }^{2} = {5}^{2} \\ x = 25$

$\sqrt{x} = 6.2 \\ { \sqrt{x} }^{2} = {6.2}^{2} \\ x = 38.44$

$\sqrt{x} = 4.3 \\ { \sqrt{x} }^{2} = {4.3}^{2} \\ x = 18.49$

$\sqrt{x} = 0.7 \\ { \sqrt{x} }^{2} = {0.7}^{2} \\ x = 0.49$

$\sqrt{x} = 3.1 \\ { \sqrt{x} }^{2} = {3.1}^{2} \\ x = 9.61$