Question

Determine o valor de X de cada triângulo abaixo ​

Answer 1

e) x² = 24²+32²

x² = 576+1024

x² = 1600

x = √1600

x = 40

f) (6√2)² = x²+x²

2x² = 36.2

2x² = 72

x² = 72/2

x² = 36

x = √36

x = 6

h) (x+5)² = (x+3)²+6²

x²+10x+25 = x²+6x+9+36

x²-x²+10x-6x = 9+36-25

4x = 20

x = 20/4

x = 5

i) (3√2)² = x²+x²

2x² = 9.2

2x² = 18

x² = 18/2

x² = 9

x = √9

x = 3

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25/05/22

Answer 2

E)
X^2 = 24^2 + 32^2
X^2 = 576 + 1024
X^2 = 1600
X^2 = 40^2
x = 40
_______________
F)
(6\/2)^2 = x^2 + x^2
36.2 = 2.x^2
36 = x^2
6^2 = x^2
X^2 = 6^2
x = 6

______________


H)
(x+5)^2 = 6^2 + (x+3)^2
x^2 + 2.5.x + 25 = 36 + x^2 + 2.3x + 9
10x + 25 = 36 + 6x + 9
10x - 6x = 45 - 25
4x = 20
x = 20/4
x = 5
______________

I)
(3\/2)^2 = x^2 + x^2
9.2 = 2x^2
9 = x^2
x^2 = 9
X^2 = 3^2
X = 3