Question

determine o valor de X​

Answer 1

${h}^{2}+{(x+8)}^{2}={12}^{2}$

${6}^{2}={h}^{2}+{x}^{2} \\ {h}^{2}+{x}^{2}=36$

${h}^{2}+{x}^{2}+16x+64=144$

$36+16x+64=144 \\ 16x=144-36-64 \\ 16x=44 \\x=\frac{44}{16} \\ x=\frac{11}{4}$