Question

Determine o valor de log2(8·32)

Answer 1

log2 8 +log2 32=
2^x=2³    2^x=2^5
x=3           x=5
3+5=8

Answer 2

$log_2\ (8\cdot32)=log_2\ (2^{3} \cdot 2 ^{5})=log_2\ 2^{3+5}=log_2\ 2^8\\ \\=8\cdot log_2\ 2=8\cdot 1=8$