Question

Determine o valor da expressão da imagem abaixo:

Answer 1

Resposta:

$S=\varnothing$

Explicação passo-a-passo:

$\frac{( {4}^{1 + log_{4}(3) } + log_{5}( {5}^{4} ) . log_{\pi}( \sqrt[4]{\pi} ) }{( log_{5}( log_{ \frac{1}{7} }( \frac{1}{7} )). log_{0.25}(0.5)} \\ \\ \frac{( {4}^{ log_{4}(4) + log_{4}(3) } + 4 log_{5}(5) ).( log_{\pi}( {\pi}^{ \frac{1}{4} } ) }{( log_{5}(1)). log_{ \frac{1}{4} }( \frac{1}{2} ) } \\ \\ \frac{( {4}^{ log_{4}(4.3) } + 4.1).( \frac{1}{4} . log_{\pi}(\pi) ) }{0.( log_{ \frac{1}{4} }(1) - log_{ \frac{1}{4} }(2) )} \\ \\ \frac{( {4}^{ log_{4}(12) } + 4).( \frac{1}{4} .1)}{0.(0 - ( - \frac{1}{2} ))} \\ \\ \frac{( {4}^{ log_{4}(12) } + 4). \frac{1}{4} }{0. \frac{1}{2} } \\ \\ \frac{ \frac{4 ^{ log_{4}(12) } }{4} + 1 }{0} \\ \\ \frac{ {4}^{ log_{4}(12) - 1} + 1}{0} \\ \\ \frac{ {4}^{ log_{4}(12) - log_{4}(4) } + 1}{0} \\ \\ \frac{ {4}^{ log_{4}( \frac{12}{4} ) } + 1}{0} \\ \\ \frac{4 ^{ log_{4}(3) } + 1}{0}$