Question

determine o vajór de p na funcao f(x)=x^2-2x+p.

Answer 1

f(x) = x² - 2x + p

a→ 1     b→ - 2    c→ p

Δ = b²  4ac

Δ = (-2)² - 4 . 1 . p

Δ = 4 - 4p

4 - 4p = 0

- 4p = 0 - 4  

- 4p = - 4 .(-1)

4p = 4

p = 4/4

p = 1