Determine o oitavo termo de uma P.A. onde a5 = 6 e a17 = 30.
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Solução!
![a17=a5+12r\\\\\
30=6+12r\\\\\
30-6=12r\\\\
24=12r\\\\
r= \dfrac{24}{12}\\\\\
r=2](https://tex.z-dn.net/?f=a17%3Da5%2B12r%5C%5C%5C%5C%5C%0A30%3D6%2B12r%5C%5C%5C%5C%5C%0A30-6%3D12r%5C%5C%5C%5C%0A24%3D12r%5C%5C%5C%5C%0Ar%3D+%5Cdfrac%7B24%7D%7B12%7D%5C%5C%5C%5C%5C%0Ar%3D2+ "a17=a5+12r\\\\\
30=6+12r\\\\\
30-6=12r\\\\
24=12r\\\\
r= \dfrac{24}{12}\\\\\
r=2")
![a8=a5+3r\\\\\
a8=6+3(2)\\\\\
a8=6+6\\\\\
a8=12](https://tex.z-dn.net/?f=a8%3Da5%2B3r%5C%5C%5C%5C%5C%0Aa8%3D6%2B3%282%29%5C%5C%5C%5C%5C%0Aa8%3D6%2B6%5C%5C%5C%5C%5C%0Aa8%3D12 "a8=a5+3r\\\\\
a8=6+3(2)\\\\\
a8=6+6\\\\\
a8=12")
Bom dia !
Bons estudos!
Solução!
Bom dia !
Bons estudos!
AliceLind:
Obrigado!!!!
Qual formula vc usou??
P.A
N, foi a an=a1+(n-1)r ??
Onde vc tirou o 12?
Da uma olhada no exercicio 6+3.2=6+6=12
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