Question

determine o coeficiente angular da reta que passa pelo. P 3, - 2 e pelo. Médio do segmento A -1,6 e B 5,2​

Answer 1

cálculo do ponto médio de A e B:

$\mathtt{x_{M}=\dfrac{x_{A}+x_{B}}{2}}\\\mathtt{x_{M}=\dfrac{-1+5}{2}=\dfrac{4}{2}=2}$

$\mathtt{y_{M}=\dfrac{y_{A}+y_{B}}{2}}\\\mathtt{y_{M}=\dfrac{6+2}{2}=\dfrac{8}{2}=4}$

Logo M (2,4).

Devemos encontrar o coeficiente angular que passa pelos pontos P(3,-2) e M(2,4).

$\mathtt{m=\dfrac{y_{M}-y_{P}}{x_{M}-x_{P}}}$

$\mathtt{m=\dfrac{4-(-2)}{2-(-2)}}$

$\mathtt{m=\dfrac{4+2}{2+2}}$

$\mathtt{m=\dfrac{6\div2}{4\div2}}$

$\huge\boxed{\boxed{\mathtt{m=\dfrac{3}{2}}}}$