Question

Determine o 11º termo da PG (1, 4, 16, 64,......)?

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{4}{1} = 4 \\ \\ \\ an = a1 \times q {}^{n - 1} \\ an = 1 \times 4 {}^{11 - 1} \\ an = 1 \times 4 {}^{10} \\ an = 1 \times 1048576 \\ an = 1048576 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant$

Answer 2

Resposta:a11=1048576

Explicação passo a passo:

a1=1,q=a2/a1--->q=4/1--->q=4,n=11,a11=?

an=a1.q^n-1

a11=1.4^11-1

a11=1.4^10

a11=1048576