Question

Determine M, o ponto médio de AB, nos seguintes casos: A (2,-2) e B (-2, -6).

a) PM (0,-3)
b) PM (1,-4)
c) PM (0,-4)
d) PM (-4,0)​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{M = \{\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\}}$

$\mathsf{M = \{\dfrac{2 + (- 2)}{2};\dfrac{-2 +(- 6)}{2}\}}$

$\mathsf{M = \{\dfrac{2 - 2}{2};\dfrac{-2 - 6}{2}\}}$

$\mathsf{M = \{\dfrac{0}{2};\dfrac{-8}{2}\}}$

$\boxed{\boxed{\mathsf{M = \{0;-4\}}}}\leftarrow\textsf{letra C}$