Question

Determine as raizes imaginárias da equação x²+36=0, então as raizes são? (explique)

Answer 1

$\mathsf{x^2+36=0}\\ \mathsf{x^2=-36}\\ \mathsf{x=\pm \sqrt{-36} }\\ \mathsf{x=\pm \sqrt{36}\cdot \sqrt{-1} }\\\\ \mathsf{ \sqrt{-1}=i }\\\\ \mathsf{x=\pm6\cdot i}\\ \mathsf{x=\pm6i}\\\\ \Large\boxed{\mathsf{S=\{6i,-6i\}}}$

Answer 2

x^2+36=0

x^2=-36

x=√-36

x=√36.√-1

x=6i ou x=-6i



espero ter ajudado!

bom dia !