Question

determine as raizes da equacao 2y2-14y+12=0

Answer 1

2y²-14y+12=0

a= 2
b= -14
c= 12

Δ= b² -4 * a *c
Δ= (-14)² -4 * 2 *12
Δ= 196 - 96
Δ= 100

-b +- √Δ / 2*a
-(-14) +- √100 / 2*2
14 +- 10 / 4

x' = $\frac{14 + 10}{4}$
x' = $\frac{24}{4}$
x' = 6

x" = $\frac{14 - 10 }{4}$
x" = $\frac{4}{4}$
x" = 1

S{ 6 e 1 }