Question

determine as medidas X,Y e Z

ME AJUDAAA

Answer 1

$8^{2}+x^{2}=16^{2} \\ 64+x^{2}=256 \\ x^{2}=192 \\ x=\sqrt{192}=8\sqrt{3} \\ (8\sqrt{3})^{2}+12^{2}=y^{2} \\ 64*3+144=y^{2} \\ y^{2}=336 \\ y=\sqrt{336}=4\sqrt{21} \\ 4^{2} + z^{2}=(4\sqrt{21})^{2} \\ 16+z^{2}=16*21 \\ z^{2}=336-16=320 \\ z=\sqrt{320}=8\sqrt{5}$