Question

Determine as coordenadas dos vértice da parábola:
a) y= 2x^2-5x+2
b) y= 2x^2-3x+1​

Answer 1

Resposta:

a) y= 2x²-5x+2 a= 2 / b= -5/ c=2

Xv= -b

----

2a

Xv= -(-5)

-------

2(2)

Xv= 5

--

4

Yv= -∆. ∆=b²-4ac

----. ∆=-5²-4.2.2

4a. ∆= 25-16

∆= 11

Yv= -(11)

---------

4.(2)

Yv= -11

------

8

V(X,Y) = ( 5 , -11 )

-- -----

4 8

b) y= 2x²-3x+1 a= 2 / b= -3/ c=1

Xv= -b

----

2a

Xv= -(-3)

-------

2(2)

Xv= 3

--

4

Yv= -∆ ∆=b²-4ac

---- ∆=-3²-4.2.1

4a ∆= 9-8

∆= 1

Yv= -(1)

---------

4.(2)

Yv= -1

------

8

V(X,Y) = ( 3 , -1 )

-- ---

4 8