Question

determine as coordenadas do vértice: y=x²-4x

Answer 1

a = 2 b= -4
Δ=b²-4ac
Δ=(-4)²-4.2.0
Δ=16
XV= -b / 2a = -(-4) / 2.2 = 4/4 = 1
YV = -Δ / 4a = -16 / 4.1 = -4

Answer 2

Xv= -b / 2a
Xv =4/2
Xv= 2

Yv = -delta / 4 a
Yv = b^2 -4ac / 4a
Yv = 16/4
Yv=4