Question

determine as coordenadas do vértice
V=(-b/2.a; -∆/4-a)

F (x)=3 x²+1​

Answer 1

Olá, boa tarde!

$Coeficientes:\;a=3,\;b=0\;e\;c=1\\\\x_v=-\dfrac{b}{2a}\\\\x_v=-\dfrac{0}{2\cdot3}\\\\x_v=-\dfrac{0}{6}\\\\x_v=0\\\\\\\\y_v=-\dfrac{\Delta}{4a}\\\\y_v=-\dfrac{b^2-4ac}{4\cdot3}\\\\y_v=-\dfrac{0^2-4\cdot3\cdot1}{12}\\\\y_v=-\dfrac{-12}{12}\\\\y_v=-(-1)\\\\y_v=1\\\\\\\boxed{Resposta:(0,1)}$

Espero ter ajudado.

Bons estudos! :)