Question

determine as coordenadas do vértice parábola dessa função 2 grau:
2x^2 -3x +1​

Answer 1

2x² - 3x + 1 = 0

a = 2

b = - 3

c = 1

∆ = b² - 4 . a . c

∆ = (-3)² - 4 . 2 . 1

∆ = 9 - 8

∆ = 1

xv = - b

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2a

xv = - (-3)

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2 . 2

xv = 3

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4

yv = - ∆

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4a

yv = - 1

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4 . 2

yv = - 1

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8

(3/4 , -1/8)