Question

determine as coordenadas do vertice da paabola de cada função abaixo; a) F(x)= -2x2+3x-1

Answer 1

Resposta:

$V(\frac{3}{4}, \frac{1}{8}).$

Explicação passo-a-passo:

$f(x)=-2x^2+3x-1\\Vx = \frac{-b}{2a} \\Vx = \frac{-3}{2(-2)}\\Vx = \frac{-3}{-4}---> \frac{3}{4}\\Vy = Substitua\\Vy = -2(\frac{3}{4})^2+3(\frac{3}{4})-1\\Vy = \frac{-9}{8}+ \frac{9}{4}-\frac{1}{1}\\Vy = \frac{-8}{8}-\frac{9}{8}+\frac{18}{8}\\Vy = \frac{-8-9+18}{8}\\Vy = \frac{1}{8}.\\\\V(Vx, Vy)\\V(\frac{3}{4}, \frac{1}{8}).\\\\Att, Felipemlvr.$