Question

Determine as coordenadas do vértice da função? ta aí: ^​

Answer 1

(Xv,Yv)= (1, 3)

$f(x) = - x {}^{2} + 2x + 2$

$a = - 1 \: \: \: b = 2 \: \: \: \: e \: \: \: c = 2$

$xv = \frac{ - b}{2a} = \frac-2/-2=1</p><p>[tex]yv = \frac{ - (b {}^{2} - 4ac) }{4a} = \frac{ - (2 {}^{2} - 4. - 1.2) }{4. - 1} = \frac{ - (4 + 8)}{ - 4} = \frac{ - 12}{ - 4} = 3$

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Answer 2

$\Large\boxed{\begin{array}{l}\sf f(x)=-x^2+2x+2\\\sf\Delta=b^2-4ac\\\sf\Delta=2^2-4\cdot(-1)\cdot2\\\sf\Delta= 4+8\\\sf\Delta=12\\\sf x_V=-\dfrac{b}{2a}\\\\\sf x_V=-\dfrac{\backslash\!\!\!2}{\backslash\!\!\!2\cdot(-1)}=1\\\\\sf y_V=-\dfrac{\Delta}{4a}\\\\\sf y_V=-\dfrac{12}{4\cdot(-1)}=3\\\\\sf\red{V(1,3)}\end{array}}$