Question

Determine as coordenadas do vértice da função f(x) = x² - 10x + 16

Answer 1

F(x)= x^2-10x+16
F(x)= x^2-10x+16= 0
Delta = b^2-4ac
a=1 b=-10 c=+16
Delta= -10^2-4(1).(16)
Delta= 100-64
Delta = 36
--------------------------------
x= -b + Raiz de Delta
_____________
2.a

X'= -(-10)+ Raiz de 36
______________ =
2.1

X'= 10+6
______________ = 16:2
2 _____ = 8/1
2:2

X''= 10 - 6
______________ = 4:2
2 ____ = 2/1
2:2
S= {8;2}

Espero ter ajudado :)