Question

Determine as coordenadas do vértice da função f(X)=-x(ao quadrado)/3+2x-5/3

Answer 1

$f(x)=-\frac{x^2}{3}+2x-\frac{5}{3}\\ \\ \boxed{x_V=\frac{-b}{2a}=\frac{-2}{2(-\frac{1}{3})}=3}$

$\boxed{y_V=f(3)=-\frac{3^2}{3}+2*3-\frac{5}{3}=-3+6-\frac{5}{3}=\frac{4}{3}}$