Question

Determine a soma dos termos da pg: 2, 2^2, ..., 2^10

Answer 1

an=a1.q^(n-1)

2^10=2.(2)^(n-1)

2^(n-1)=2^10/2

2^(n-1)=2^(10-1)

2^(n-1)=2^9

n-1=9

n=9+1

Sn=a1.(q^n-1)/q-1

sn=2.[(2)^1-1]/2-1

Sn=2.[1024-1]/1

Sn=2.[1023]

Sn=2046


espero ter ajudado!

boa tarde!