Question

determine a soma dos infinitos termos da pg (2/3,2/9,...)

Answer 1

Q = a₂/a₁
Q = 2/9 . 3/2
Q = 6/18
Q = 1/3

$S_{\infty} = \frac{a_{1}}{1 -q}$
S∞ = (2/3)/(2/3 -1)
S∞ = (2/3)/(-1/3)
S∞ = 2/3 . -3/1
S∞ = -6/3
S∞ = -2